The matrix showing the numbers of points per line, and vice versa, class by class is:
| q2ν+qν+1 | qν(q3ν-1) | q4ν(q2ν+qν+1) | q5ν(q3ν-1) | ||
|---|---|---|---|---|---|
| s | t1 | t2 | x | ||
| q2ν+qν+1 | C0 | qν+1,qν+1 | 1,q2ν-qν | 1,q4ν | 0,0 |
| qν(q3ν-1) | C11 | q2ν-qν,1 | q2ν,q2ν | 0,0 | 1,q4ν |
| q6ν | C12 | 0,0 | 0,0 | q2ν,q2ν+qν+1 | q2ν,qν(q3ν-1) |
The complete design above is a BIBD with λ=1.
The structure of the hyperplane is easily ascertained. The plane of type B0 is given in the 2x2 subtable top left.
There must be q4ν(q2ν+qν+1) more tangents, hence the t2, which necessarily must use a separate class of C1 points. Finally, the exterior lines give the concurrences between the C11 and C12 points: since all the concurrences within the C11 points have been obtained in the plane of type B0 aforementioned, they can appear only singly in the exterior lines, hence the form given.
The rest of the table then follows by simple calculations.
A table showing the relationship between the points and hyperplanes of PG(4,q2ν) is as follows.
| (q5ν-1)/(qν-1) | qν(q2ν+1)(q5ν-1) | ||
|---|---|---|---|
| D0 | D1 | ||
| (q5ν-1)/(qν-1) | C0 | q3ν+q2ν+qν+1,q3ν+q2ν+qν+1 | q2ν+qν+1,qν(q2ν+1)(q3ν+1) |
| qν(q2ν+1)(q5ν-1) | C1 | qν(q2ν+1)(q3ν+1),q2ν+qν+1 | q6ν+q4ν-qν,q6ν+q4ν-qν |
The complete design above is a BIBD with λ=q4ν+q2ν+1.
My conjectured table showing the relationship between the points and planes of a hyperplane of type D1 is as below. The planes of types B1 and B2 are shown here.
| 1 | q2ν(q2ν+qν+1) | q3ν(q3ν-1) | ||
|---|---|---|---|---|
| B0 | B1 | B2 | ||
| q2ν+qν+1 | C0 | q2ν+qν+1,1 | qν+1,q2ν(qν+1) | 1,q3ν(qν-1) |
| q4ν-qν | C11 | q4ν-qν,1 | q2ν-qν,q2ν | q2ν,q4ν |
| q6ν | C12 | 0,0 | q4ν,q2ν+qν+1 | q4ν,qν(q3ν-1) |
The complete design above is a BIBD with λ=q2ν+1.
Last Updated on 04/05/2004
By D.H.Rees