A PG(3,2) gives a BIBD(15,35,7,3,1). Using homogeneous coordinates x and y to denote the points, a plane is represented by the equation α'x=0. The correlation may be defined by x'Py=0: to the point x corresponds the set of points y such that (x'P)y = 0 (and vice versa). Here, the matrix adopted is:
| 0 | 1 | 0 | 0 |
| 1 | 0 | 0 | 0 |
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| Point | Coords | Plane |
| A | (0001) | a,d,e,h,i,l,m |
| B | (0010) | b,d,f,h,j,l,n |
| C | (0011) | c,d,g,h,k,l,o |
| D | (0100) | a,b,c,d,e,f,g |
| E | (0101) | a,d,e,j,k,n,o |
| F | (0110) | b,d,f,i,k,m,o |
| G | (0111) | c,d,g,i,j,m,n |
| H | (1000) | a,b,c,h,i,j,k |
| I | (1001) | a,f,g,h,i,n,o |
| J | (1010) | b,e,g,h,j,m,o |
| K | (1011) | c,e,f,h,k,m,n |
| L | (1100) | a,b,c,l,m,n,o |
| M | (1101) | a,f,g,j,k,l,m |
| N | (1110) | b,e,g,i,k,l,n |
| O | (1111) | c,e,f,i,j,l,o |
By constructing the lines of the geometry from the points, and the corresponding lines from the intersections of the corresponding planes, the following partial design is obtained (in resolved form):
| BHJ,bhj | ALM,alm | FIO,fio | EKN,ekn | CDG,cdg |
| AHI,ahi | FKM,fkm | CLO,clo | BEG,djn | DJN,beg |
| CKH,ckh | ADE,ade | GIN,gin | BMO,fjl | FJL,bmo |
| BLN,bln | GHO,cij | AJK,ehm | CEF,dko | DIM,afg |
| BDF,bdf | EHM,ajk | CIJ,gho | GKL,cmn | ANO,eil |
| GJM,gjm | FHN,bik | ABC,dhl | DKO,cef | EIL,ano |
| EJO,ejo | DHL,abc | BIK,fhn | CMN,gkl | AFG,dim |
All that remains is to match the points within the lines: in the original paper this was done by trial-and-error, but some improvement to that can be made.